Be notified that I am not an organic chemist (I AM a chemist though) and here is what I think.
mols AgCl = grams/molar mass = 0.718/143.3 = 0.005
mols B = 0.805/161 = 0.005
a. According to the data above, there is 1 Cl atom in each molecule of B.
b. We might expect 2, of course, from the formula; howeverr, what we have is a molecule that has the Cl atoms attached in different ways. One can be pulled off easily and the other stays attached. So the AgNO3 shows just one because only one atom Cl per molecule B was hydrolyzed.
c. The best choice I can come up with, and I've spent more than three hours trying this and trying that (an organic chemistry would have known enough s/he would have known exactly what to do) is 4-chlorobenzyl chloride. The Cl on the CH2Cl part of B is the one we find in hydrolysis. The Cl attached to the 4 position of the benzene ring does not give the Cl/AgNO3 test.
Hope this helps.
Hydrolysis of a compound B(C7H6CL2) was carried out by refusing with excess potassium hydroxide solution.The resulting solution was acidified with dilute nitric acid and excess silver nitrate added to precipitate the chloride ions as Silver Chloride, 0.718g was found from 0.805g of B
a. Calculate the number of chlorine atoms present in each molecule of B which are liberated by hydrolysis.
b. Suggest an explanation for result obtain in a.
c. Give a possible structure of B.
2 answers
The answers are correct, but I don't really comprehend the answer for c
1 answer