Hydrogen selenide (H2Se) reacts with water according to the following question.

H2Se+H2O SeH-+H3O+
In three to five sentences, identify the acid, base, conjugate acid, and conjugate base in this reaction. Use the periodic table to explain why each substance acted as the acid or the base in this reaction.

1 answer

In the reaction between hydrogen selenide (H₂Se) and water (H₂O), H₂Se acts as the acid because it donates a proton (H⁺) to the water. The water serves as the base in this reaction because it accepts the proton. When H₂Se donates a proton, it forms the conjugate base, selenide ion (SeH⁻), while water becomes the conjugate acid, hydronium ion (H₃O⁺).

The reason H₂Se acts as an acid relates to its position in the periodic table; selenium (Se) is a chalcogen located beneath sulfur (S), which is known to form weak acids by donating protons. On the other hand, water, as a polar molecule with a bent structure and a high electronegativity of oxygen, can easily accept protons and function as a base. This interaction highlights the acid-base behavior based on the ability of substances to donate or accept protons in reactions.