Hydrogen selenide (H2Se) reacts with water according to the following equation.

Question

H2Se + H2O → SeH– + H3O+

Identify the acid, base, conjugate acid, and conjugate base in this reaction

(4 points)
H2Se is a(n)



H2O is a(n)

SeH– is a(n)

H3O+ is a(n)

Answer 1

In the reaction you provided:

\[ \text{H}_2\text{Se} + \text{H}_2\text{O} \rightarrow \text{SeH}^- + \text{H}_3\text{O}^+ \]

we can identify the following:

1. H2Se is a(n): Acid (specifically, it acts as a Brønsted-Lowry acid because it donates a proton, H⁺).

2. H2O is a(n): Base (it acts as a Brønsted-Lowry base because it accepts a proton, H⁺).

3. SeH– is a(n): Conjugate base (it is the species formed when H₂Se donates a proton).

4. H3O+ is a(n): Conjugate acid (it is the species formed when H₂O accepts a proton).

So, to summarize:

• H2Se is an acid.
• H2O is a base.
• SeH– is a conjugate base.
• H3O+ is a conjugate acid.