integral of x^n dx = (1/(n+1)) x^(n+1) in general
integral of x^-2 dx = (1/-1) x^-1
which is( 1/x ) + constant of integration
the right side is -k t + constant of integration
1/x = -k t + c
x = 1/ (-kt+c)
undefined when kt = c
how would i solve the differential equation
dx/dt=-kx^2
i.e. solve for x as a function of t.
I've been told to rearrange the equation to yield
dx/x^2=-k dt
but what can and should I do now?
1 answer