How would i found out the freezing point of a solution which has 0.05mol of acetic acid dissolved into 125g of benzene? Benzene melts at 5.5C and has a constant of 5.1C/m. The acid forms a dimer (what is this and how does it affect the calculations?)
A dimer is a molecule from from two of the same atoms or molecules. Acetic acid dimer would be (HC2H3O2)2
When a dimer forms, there would be half as many molecules of solute in solution when you apply Raoult's law for the freezing point lowering. They apparently tell you the Raoult's Law coefficient for benzene. You need to calculate the molal concentration of the acetic acid dimer, and apply the law.
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