How would I find point slope form, slope intercept form, and standard form for these three sets of coordinates. (5,3) (5,-1) (2,6) (4,-2) (-4,-3) (-1,-4)
2 answers
Sorry, the coordinates were not in the correct order just ignore them and explain how to do point slope form, slope intercept form and standard form if you can please.
point slope relies on the fact that the slope m of a line is constant. So, for any point (x,y) on the line through (h,k), the slope
(y-k)/(h-k) = m
slope-intercept just reflects the fact that if the slope is m, every time x changes by 1, y changes by m.
so, y = mx
That intersects the axes at (0,0). If you know the y-intercept is y=b, the slope doesn't change, so
y = mx+b
don't know what you want to say about the standard form ax+by=c. That's just the way it's written.
(y-k)/(h-k) = m
slope-intercept just reflects the fact that if the slope is m, every time x changes by 1, y changes by m.
so, y = mx
That intersects the axes at (0,0). If you know the y-intercept is y=b, the slope doesn't change, so
y = mx+b
don't know what you want to say about the standard form ax+by=c. That's just the way it's written.