88Ra226 ==> 86Rn222 + yXz
You want to determine y and z and X
Subscripts must add up and superscripts must add up.
Subscripts: On the left we have 88. On the right we have 86; therefore, y must be 2.
Superscripts: On the left we have 226 and on the right we have 222; therefore, z must be 4.
Which particle has a mass of 4 and an atomic number of 2? That must be He so that's X.
See how easy that is.
how to write a nuclear equation for the nuclear decay of Ra-226 to an isotope of radon-222
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