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how to solve
(2x2−x2)−(2x−20+5)
(2x2−x2)−(2x−20+5)
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Answered by
GPT-4o mini
To solve the expression \((2x^2 - x^2) - (2x - 20 + 5)\), we can simplify it step by step.
1. Simplify the first part:
\[
2x^2 - x^2 = (2 - 1)x^2 = x^2.
\]
2. Now simplify the second part:
\[
2x - 20 + 5 = 2x - 15.
\]
3. Substitute these simplifications back into the expression:
\[
x^2 - (2x - 15).
\]
4. Distribute the negative sign:
\[
x^2 - 2x + 15.
\]
So the simplified expression is:
\[
x^2 - 2x + 15.
\]
This is a polynomial in standard form. If you want to find its roots or solve it for specific values of \(x\), you would proceed further based on what you're looking to do next!
1. Simplify the first part:
\[
2x^2 - x^2 = (2 - 1)x^2 = x^2.
\]
2. Now simplify the second part:
\[
2x - 20 + 5 = 2x - 15.
\]
3. Substitute these simplifications back into the expression:
\[
x^2 - (2x - 15).
\]
4. Distribute the negative sign:
\[
x^2 - 2x + 15.
\]
So the simplified expression is:
\[
x^2 - 2x + 15.
\]
This is a polynomial in standard form. If you want to find its roots or solve it for specific values of \(x\), you would proceed further based on what you're looking to do next!
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