how to find the slope of the curve 17x^2+12xy=100-8y^2 at the point where y=1.
-i already d/dx but i didn't know how to find the slope of curve bcus they only give y.
d/dx=(-34x-12y)/(12x+16y)
-i already d/dx but i didn't know how to find the slope of curve bcus they only give y.
d/dx=(-34x-12y)/(12x+16y)