How to divide a right angled triangle into two isosceles triangle ? Kindly help

2 answers

construct perpendicular bisectors on the two shorter sides (non hypotenuse)

the bisectors will intersect the hypotenuse at the vertices of the two isosceles triangles

the common side for the triangles is the line from the intersection to the right angle
or even simpler:
draw a median from the right-angle to the hypotenuse.

proof:
let the triangle be A(0,0), B(b,0) and C(0,c)
let AD be the median.
midpoint of BC = ( (b/2 , c/2)
AD = √(b^2/4 + c^2/4)

BD = √(b - b/2)^2 + (c/2-0)^2 ) = CD
= √( b^2/4 + c^2/4)
= AD
Similar Questions
  1. Write this answer a bit different.Based on the given figure above, we can conclude that the triangle is an isosceles triangle.
    1. answers icon 1 answer
    1. answers icon 6 answers
  2. Which of the statements is ALWAYS TRUE?A-A right triangle is a scalene triangle. B-An equilateral triangle is an isosceles
    1. answers icon 5 answers
  3. If in a triangle ABC,c(a+b) Cos B/2 =b(c+a) Cos C/2 then the triangle is :- 1. isosceles 2. Right angled 3. isosceles or right
    1. answers icon 3 answers
more similar questions