Asked by Deepak
Perimeter of a right angled trangle is 40 cm. Hypotenus is 17cm. Find the area.
Urgent help required. Thanks in advance
Urgent help required. Thanks in advance
Answers
Answered by
Reiny
..which would leave 40-17 or 23 as the sum of the other two legs
Let one leg be x, then the other is 23-x
x^2 + (23-x)^2 = 17^2
x^2 + 529 - 46x + x^2 = 289
2x^2 - 46x + 240 = 0
x^2 - 23x + 120 = 0
(x-15)(x-8) = 0
x = 15 or x = 8
if one leg is 15, the other is 23-15 = 8 and vice versa.
Area = (1/2)base x height
= (1/2)(15)(8) = 60
Let one leg be x, then the other is 23-x
x^2 + (23-x)^2 = 17^2
x^2 + 529 - 46x + x^2 = 289
2x^2 - 46x + 240 = 0
x^2 - 23x + 120 = 0
(x-15)(x-8) = 0
x = 15 or x = 8
if one leg is 15, the other is 23-15 = 8 and vice versa.
Area = (1/2)base x height
= (1/2)(15)(8) = 60
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