How much volume of ethane

would be required to produce 1.12 dm
3 of carbon (IV) oxide on
combustion in sufficient oxygen?
2C2H6(g)+7O2 -> 4CO2(g) + 6H2O�

3 answers

At the same T and P, we can use a shortcut and use volume as if it were mols. So 1.12 dm^3 x (2 mol C2H6/4 mols CO2) = 1.12 x 1/2 = ?

I don’t undertand
Like how?

I don't understand