Suppose the cup contains 250cc of water.
Mass of 250cm^3 of water=250g
Molecular weight of water=18g
No.of molecules in 18 g of water=6.023*10^23
No.of molecules in 250g of water=6.023*10^23*250
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18
As each molecule of water contains 10 electrons,therefore,total no.of electrons
n= 10*6.023*10^23*250
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18
=8.365*10^25
As q=ne
q=8.365*10^25*1.6*10^-19 c
=1.338*10^7 c
How much positive and negative charge is there in a cup of water
7 answers
That was heroic Elsa tony !
I wrote in the 2 steps all divided by 18.OK..
What do u mean Damon???
I mean I often answer physics questions here and you saved me a lot of work :)
Fine I understood..anyway thank u...:)))
How much of positive and negative charges are present in a cup of water? Assume the mass of water in the cup to be 250 g.