How much of a(n) 60% orange juice drink must be mixed with 8 gallons of a 30% orange juice drink to obtain a mixture that is 50% orange juice?
2 answers
.6 x + (.3 * 8) = .5 (8 + x)
.6x + .3(8) = .5(x+8)
times 10
6x + 24 = 5x + 40
x = 16
times 10
6x + 24 = 5x + 40
x = 16