how much of 55% nitric acid, specific gravity 1g/ml is needed to prepare 100ml of 0.01M Nitric acid

Answer 1

First, calculate the molarity of the HNO3 solution you have.
That's 1000 mL x 1 g/mL x 0.55 x (1 mol/63 g) = 8.73 M
Then use the dilution formula of
mL1 x M1 = mL2 x M2
mL1 x 8.73 = 100 x 0.01
Solve for mL1, transfer that amount of the HNO3 to a 100 mL volumetric flask, add distilled water to the mark on the flask, stopper, mix thoroughly, label. done.