h2so4 is labelled as 9.8 by weight. specific gravity of h2so4 is 1.8. the volume of acid to be taken to prepare 100 ml of 0.18M solution is?

Answer 1

Is that 9.8% w/w? I assume so. Then the molarity of the H2SO4 is
1000 mL x 1.8 g/mL x (9.8/100) x 1/98 = ? which I will label as y.
Then mL1 x M1 = mL2 x M2
....100 mL x 0.18 = mL2 x y
Solve for mL2

Answer 2

10 ml

Answer 3

M=10×d×y÷gram molecular weight
M=10(1.8)9.8 ÷ 98
M=1.8
M1×V2=M2×V1
(1.8)V2=1000(0.18)
V2=100ml

Answer 4

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Answer 5

Dirty