How much ice (in grams) would have to melt to lower the temperature of 53.4g of water from 65 C to 0C?

Question

I know there are more than one step here, I would appreciate an answer that does not do the work for me, but show me how to lay out the problems and in which order... thank you!

Answer 1

the sum of heats gained is zero.

Heatgainedicemelting+heatgainedwater=0
massice*Hf+53.4grams*specificheatwater*(0-65)=0

massice=53.4g*1cal/gramC *53.4C / 80cal/g

= 53.4*65/80 grams

Answer 2

Thank you Bob for your time! I believe there was a misunderstanding in the question,my mistake... C is equal to degree celcius.

Answer 3

Note the correct spelling of celsius.
Celsius is all that is needed. It need not be converted to kelvin.

Answer 4

Thank you again!