How much heat does your body lose when 3.15g of sweat evaporates from your skin at 25 ∘C? (Assume that the sweat is only water.) The heat of vaporization of water at 25 ∘C is 44.0 kJ/mole?

Question

Please someone help explain how to set up this problems or how to do it

Answer 1

It's the old q = m*heat vaporization
m = 3.15g/18 = ? mols H2O
heat vap = 44.0 kJ/mol
q = ? kJ.