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How much heat does your body lose when 3.05 g of sweat evaporates from your skin at 25 ∘C? (Assume that the sweat is only water.) The heat of vaporization of water at 25 ∘C is 44.0 kJ/mole.

Answer:
3.05g H2O*1mol/18.015gH2O= 0.169mol H2O
0.169mol*44.0kJ/1mol= 7.45kJ

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