How much energy will be liberated upon the combustion of 12.5 grams of ethene?
C2H4(g) + 3O2(g) ----> 2CO2(g) + 2H2O(g)
Delta H = -1387.4 kj
1 answer
q = 1387.4 kJ x (12.5 g/26 g) = ? kJ liberated
C2H4(g) + 3O2(g) ----> 2CO2(g) + 2H2O(g)
Delta H = -1387.4 kj
1 answer