how much energy is required to change 40 g of ice at -10 C to steam at 110 C?

Answer 1

This is a three part question.

First part is to calculate the amount of energy necessary to turn -10 C ice into 0 C water. Next is calculating the energy to convert 0 C water into 100 C steam. Then calculating the amount of energy to raise the steam 10 C to 110 C.

Use
Q=mcΔT

Q is heat energy
m is the mass of the thing
c is the specific heat capacity constant which is different depending on the material
ΔT is the change in temperature caused by the heat energy (or vice versa).

You also need to account for the Latent Heat of Fusion for Ice and Latent Heat of Vaporization for Steam, which is why phase changes are important.

In addition, the specific heat capacity value is different for each stage of water.

Part 1:
Q = 40g*(2.108 j/g*K)*(10)

Amount of heat energy necessary to go from -10 C ice to 0 C ice. Now add the latent head of fusion times the amount of mass to the Q value you just calculated. (334 j/g*40 g).

Do the same for the other parts of the questions.

Answer 2

Best solution thanks