Change 5 lbs ice to grams. 5 lbs x (459.6 g/1 lb) = 2298 grams.
Change 32 F to C. That's 0o C.
Cjamge 212 F tp C/ Tjat's 100c C.
q1 = heat to melt the ice at zero C to liquid @ zero C.
q1 = mass ice x heat fusion = ? You will need to look heat fusion.
q2 = heat to move liquid water from zero C to 100 C
q2 = mass water x specific heat H2O x (Tfinal-Tinitial) = ? You will need to look up the specific heat H2O
q3 = heat to convert liquid H2O @ 100 C to steam @ 100 C.
q3 = mass H2O x heat vaporization = ? You will need to look up the heat of vaporization for water.
Total heat = Qtotal = q1 + q2 + q3 = ?
Post your work if you get stuck. When looking up the values above make sure to use units consistent with the other parts of the problem. For example, if you're using grams you want to use specific heat water in J/g*C
calculate the heat required to change 5 lbs of 32°f ice to 212f° steam
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