nobody knows because you did not give me:
specific heat of ice
heat of fusion of water
specific heat of water
heat of vaporization of water
Cp of steam
Energy =
10 grams (or .010 kg if using kg)
times the sum of:
[5 deg * spec heat ice
+ heat of fusion of water
+ 100 deg * spec heat of water
+ heat of vaporaization of water
+ 5 deg * specific heat of steam at one atmosphere ]
How much energy is required to bring 10.0 grams of ice at -5.00 degrees to 105-degree steam? Assume the system is isolated so that no mass is lost to the surroundings
1 answer