q1 = heat released in steam moving from 130 C to 100 C.
q1 = mass steam x specific heat steam x (Tfinal-Tinitial).
q2 = heat released in condensing steam at 100 C to liquid water at 100 C.
q2 = mass steam x heat vaporization.
q3 = heat released in moving liquid water from 100 C to 73.5 C.
q3 = mass water x specific heat water x (Tfinal-Tinitial).
Total q = q1 + q2 + q3
How much energy (in kilojoules) is released when 12.8 g of steam at 130.0 C is condensed to give liquid water at 73.5 C? The heat of vaporization of liquid water is 40.67 kJ/mol, and the molar heat capacity is 75.3 J/(K*Mol)for the liquid and 33.6 J/(K*Mol) for the vapor.
1 answer
1 answer