.025 L * .0030 M = 7.5E-5 moles
barium hydroxide has two OH- per molecule , so you need half the number of moles
? L * .020 M = 7.5E-5 / 2 moles
How much 0.020 M Ba(OH)2 is need to titrate 25.0 mL of 0.0030M HCl to the endpoint?
I'm so confused; please help!
1 answer