To determine how many times larger \( 9 \times 10^{-8} \) is than \( 3 \times 10^{-12} \), you can divide the two values:
\[ \text{Ratio} = \frac{9 \times 10^{-8}}{3 \times 10^{-12}} \]
Now, simplify the fraction:
\[ = \frac{9}{3} \times \frac{10^{-8}}{10^{-12}} \]
\[ = 3 \times 10^{-8 - (-12)} \]
\[ = 3 \times 10^{-8 + 12} \]
\[ = 3 \times 10^{4} \]
Thus, \( 9 \times 10^{-8} \) is \( 3 \times 10^{4} \) times larger than \( 3 \times 10^{-12} \).
The correct response is:
3×10⁴ (3 times 10 to the 4th power)