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9x + 7x + 8 = −4 + 4(3x+5)

One solution

Infinitely many solutions

No solutions

1 answer

To solve the equation \( 9x + 7x + 8 = -4 + 4(3x + 5) \), we can start simplifying both sides.

First, combine like terms on the left side:

\[ 9x + 7x = 16x \] Thus, the left side becomes:

\[ 16x + 8 \]

Next, let's simplify the right side of the equation:

\[ -4 + 4(3x + 5) \] Distributing the \(4\) gives:

\[ 4 \cdot 3x + 4 \cdot 5 = 12x + 20 \] So the right side simplifies to:

\[ -4 + 12x + 20 = 12x + 16 \]

Now we can rewrite the equation as:

\[ 16x + 8 = 12x + 16 \]

Next, we will isolate \(x\). Subtract \(12x\) from both sides:

\[ 16x - 12x + 8 = 16 \] This simplifies to:

\[ 4x + 8 = 16 \]

Next, subtract \(8\) from both sides:

\[ 4x = 16 - 8 \] Which simplifies to:

\[ 4x = 8 \]

Now, divide both sides by \(4\):

\[ x = 2 \]

This gives us one solution: \(x = 2\).

Since there is only one solution, we conclude:

One solution.