How many solutions does the equation x^2 - 2x - 2 = 0 have?

Answer 1

Two. The equation is degree two.

x=(2+-sqrt(4+8))/2= 1+-sqrt3

(x-1+sqrt3)(x-1-sqrt3)=
x^2-2x-1-3+sqrt3-sqrt3=x^2-2x-2