To calculate the number of potassium ions in 94 grams of potassium oxide, we first need to determine the molar mass of potassium oxide (K2O).
The molar mass of K2O is calculated as follows:
- Molar mass of potassium (K) = 39.10 g/mol
- Molar mass of oxygen (O) = 16.00 g/mol
Therefore, molar mass of K2O = 2(39.10) + 16.00 = 94.20 g/mol
Next, we calculate the number of moles of K2O in 94 grams:
Number of moles = Mass / Molar mass
Number of moles = 94 g / 94.20 g/mol = 1 mole
Since the formula for potassium oxide is K2O, it contains 2 potassium ions per molecule of K2O. Therefore, 1 mole of K2O contains 2 moles of K ions.
Lastly, we calculate the number of potassium ions in 94 grams of potassium oxide:
Number of potassium ions = 2 moles K ions x (6.022 x 10^23 ions/mol)
Number of potassium ions = 1.20 x 10^24 potassium ions
Therefore, there are approximately 1.20 x 10^24 potassium ions in 94 grams of potassium oxide.
How many potassium ions are there in 94 grams of potassium oxide
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