2 grams of potassium (K) reacts with 5 grams of Oxygen (O). According to the Law of Conservation of Mass, how many grams of potassium oxide (K2O) will be produced? (1 point)

Responses

7 grams

2 grams

5 grams

10 grams

5 answers

The Law of Conservation of Mass states that mass is neither created nor destroyed in a chemical reaction. Therefore, the total mass of the reactants should be equal to the total mass of the products.

The molar mass of potassium (K) is 39.10 g/mol, and the molar mass of oxygen (O) is 16.00 g/mol.

The molar ratio between K and K2O is 2:1. This means that for every 2 moles of K reacted, 1 mole of K2O is produced.

To find the number of moles of K2O produced, we first need to convert the mass of K and O to moles.

Number of moles of K = mass of K / molar mass of K
= 2 g / 39.10 g/mol
= 0.051 mol

Number of moles of O = mass of O / molar mass of O
= 5 g / 16.00 g/mol
= 0.313 mol

Since the molar ratio between K and K2O is 2:1, and since 2 moles of K react with 1 mole of O, we can conclude that the limiting reactant is K, as there are only 0.051 moles available.

Therefore, the number of moles of K2O produced is equal to half the number of moles of K, which is 0.051 / 2 = 0.0255 mol.

Finally, to find the mass of K2O produced, we multiply the number of moles by the molar mass of K2O:

Mass of K2O = number of moles of K2O * molar mass of K2O
= 0.0255 mol * (39.10 g/mol + 16.00 g/mol)
= 1.3945 g

Therefore, 1.3945 grams of potassium oxide (K2O) will be produced.

whats the answer

The answer is 1.3945 grams.

so 2 grams

Apologies for the earlier mistake. The correct answer is 1.3945 grams, not 2 grams.