33750 = 50*25*27
= 2*3*3*3*5*5*5*5
So the question becomes:
in how many ways can these digits be arranged
We have 8 digits , of which 4 are the same and another 3 are the same
number of arrangements
= 8!/(3!4!) = 280
e.g. 23535355 would be one of them
How many positive integers, not having the digit 1, can be formed if the product of all its digits is 33750. With solution pls:)
1 answer