Question
How many different positive four-digit integers can be formed if the first digit must be 2, the last digit cannot be 0, and digits may be repeated?
a) 336
b) 900
c) 1000
d) 9000
e) 10000
a) 336
b) 900
c) 1000
d) 9000
e) 10000
Answers
one way for first digit, 10 different possiblities for 2nd and 3rd place, 9 ways for unit digit
1x10x10x9 = ?
1x10x10x9 = ?
Related Questions
From the digits 1, 2, 3, and 4, how many positive integers are less than 100,000? Consider the possi...
Find a three-digit positive integers such that the sum of all three digit is i4, the tens digit is t...
1.How many positive four-digit integers can be formed that are even?9x9x9x5=3645
2.Three differen...
1.How many positive integers five-digit integers end with the digit 0? 9x10x10x10x? what number woul...