amount of the 1% stuff to be added ---- x ounces
.1x + .4(100) = .16(x + 100)
solve for x
How many ounces of 1% antifreeze solution must be added to 100 ounces of 40%
antifreeze solution to obtain a 16% antifreeze solution?
how do I set this equation up?
3 answers
but first change .1x to .01x
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Thanks Steve, how sloppy of me