Asked by tor
A radiator contains 6 liters of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 33% antifreeze solution?
Answers
Answered by
Steve
If x is drained, then
.25(6-x) + 1.00(x) = .33(6)
.25(6-x) + 1.00(x) = .33(6)
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