How many of the following equations have the solution set {5}

Question

?

2(x−3)+1=5

3b/15=1

2h−30=40

(1 point)
The number of equations that have the solution set {5}
is
.
Remaining Attempts : 3

Answer 1

To determine how many of the given equations have the solution set \({5}\), we will solve each equation and see if \(x = 5\) is the only solution.

1. Equation: \(2(x - 3) + 1 = 5\)

   \(2(x - 3) + 1 = 5\)

   Subtract 1 from both sides:

   \(2(x - 3) = 4\)

   Divide by 2:

   \(x - 3 = 2\)

   Add 3 to both sides:

   \(x = 5\)

   So, the solution set for this equation is \({5}\).

2. Equation: \(\frac{3b}{15} = 1\)

   Multiply both sides by 15:

   \(3b = 15\)

   Divide by 3:

   \(b = 5\)

   Therefore, the solution set for this equation is also \({5}\).

3. Equation: \(2h - 30 = 40\)

   Add 30 to both sides:

   \(2h = 70\)

   Divide by 2:

   \(h = 35\)

   Therefore, the solution set for this equation is \({35}\).

Now we summarize:

• The first equation gives a solution set of \({5}\).
• The second equation gives a solution set of \({5}\).
• The third equation gives a solution set of \({35}\).

Thus, the total number of equations that have the solution set \({5}\) is 2.

The number of equations that have the solution set {5} is 2.