Question
how do you come up with a equation for a line?? helpppp!!!!
Answers
Damon
What are you given? two points? point and slope?
Anonymous
you have to find the slope then do this formula. y=mx+b and plug it in.
Damon
That is exactly what I would do.
find the slope (Y2-Y1)/(X2-X1)
call it m
like if point 1 was (2,1) and point 2 was (3,6)
m = (6-1)/(3-2) = 5
then you have something like
y = 5 x + b if m came out 5
now all you have to do is put one point in and solve for b
like if point 1 was (2,1)
1 = 5 (2) + b
1 = 10 + b
b = -9
so the line is
y = 5 x - 9
find the slope (Y2-Y1)/(X2-X1)
call it m
like if point 1 was (2,1) and point 2 was (3,6)
m = (6-1)/(3-2) = 5
then you have something like
y = 5 x + b if m came out 5
now all you have to do is put one point in and solve for b
like if point 1 was (2,1)
1 = 5 (2) + b
1 = 10 + b
b = -9
so the line is
y = 5 x - 9
TAG
To find the slope of a line: use this equation: (y2-y1)divided by (x2-x1
EX. your two points are (4,2) and (5,5). The equation would go like this: (5-2)/(5-4)=3/1=3. Therefore, the slope of the line is 3.
About the y=mx+b, you plug in the slope in place of x and the y-intercept in place of b (I'm pretty sure the y-intercept is the point at which the line meets up with the y-axis [in this case, is (0,-10),], so b would be -10). Leaving the resulting equation as y=3x-10.
So to solve this, use the formula for slope, find the y-intercept, and plug in the two values. Hope this helps!
EX. your two points are (4,2) and (5,5). The equation would go like this: (5-2)/(5-4)=3/1=3. Therefore, the slope of the line is 3.
About the y=mx+b, you plug in the slope in place of x and the y-intercept in place of b (I'm pretty sure the y-intercept is the point at which the line meets up with the y-axis [in this case, is (0,-10),], so b would be -10). Leaving the resulting equation as y=3x-10.
So to solve this, use the formula for slope, find the y-intercept, and plug in the two values. Hope this helps!