How many numbers with 5 different digits and that are multiples of 2 can be formed with 4,5, 6, 7, 8? How many multiples of 5 could be formed with the same numbers and without repeating them?

Answer 1

first part: multiples of 2
this simply means that your number must be even, so it ends in either
4, 6, or 8 . The rest of the places have no restriction.
number of ways = 4*3*2*1*3 = 72

2nd part: multiples of 5, it can only end in 5
number of ways = 4*3*2*1*1 = 24