How many moles of nitrate ions are present in 24.0mL of a 2.93M solution of potassium nitrate?

I'm thinking this is some form of unit conversion problem I know that M= molarity which is mol/L how ever I am confused on how to set this up and input information or if I'm on the wrong track.

1 answer

You're on the right path. M = mols/L so mols = M x L
You know M and L, calculate mols KNO3. Since there is 1 mol nitrate ion in 1 mol KNO3, then mols NO3^- = mols KNO3.