How many moles of compound are present in 17g of Fe2O3?
I think I know how to do this, so if someone can show me so I can check my work against it. My answer was .106 moles of Fe2O3.
3 answers
Why don't you show how you did it ans let us check your work.
Well, If Fe atomic mass is 55.85 and O is 16, then multipy 55.85 by two and 16 by 3 and get 159.7 g/mol. Then divide 17g by 159.7 g/mol and get .106 moles.
You are absolutely correct. Good work.
1 answer