How many moles of Ca(OH)2 are produced when 9.19 grams of CaH2 and 7.90 grams of H2O react ?

Answer 1

The reaction is as followed:

CaH2 +2H2O------> Ca(OH)2 +2H2

9.19 g of CaH2/42.1 g of CaH2 *mol-1= moles of CaH2

7.90 g of H20/18g of H20 *mol-1=moles of H20

CaH2 is the limiting reagent.

moles of CaH2=moles of Ca(OH)2

moles of Ca(OH)2 *molecular mass of Ca(OH)2= mass of Ca(OH)2 in g.