Part 1 of 2:
3.1 L of a 0.46 M solution
Number of moles = volume (L) x concentration (M)
Number of moles = 3.1 L x 0.46 mol/L
Number of moles = 1.426 mol
Therefore, 3.1 L of a 0.46 M solution contains 1.426 mol of C6H12O6.
310. mL of a 0.65 M solution
Convert 310. mL to liters: 310. mL = 0.310 L
Number of moles = volume (L) x concentration (M)
Number of moles = 0.310 L x 0.65 mol/L
Number of moles = 0.2015 mol
Therefore, 310. mL of a 0.65 M solution contains 0.2015 mol of C6H12O6.
How many moles of C6H12O6 are contained in each volume of aqueous C6H1206 solution? Be sure each of your answer entries has the correct number of
significant figures.
Note: Reference the SI prefixes table for additional information.
Part 1 of 2
3.1 L of a 0.46 M solution
mol C6H126
310. mL of a 0.65 M solution
mol C6H126
1 answer