molar mass C6H12O6 = 180
mols glucose = grams/molar mass = 10.00/180 = ?
molality = mols glucose/kg solvent = mols glucose/0.500 = ?
A solution is prepared by dissolving 10.00 g of glucose, C6H12O6, in 500 g of water. The
final volume of the solution is 415 mL
i)Determine the moles of glucose, C6H12O6
ii)Calculate the molality of the solution
1 answer
1 answer