How many molecules of ethane are present in 0.862 g of c2h6

Answer 1

To find the number of molecules of ethane (C2H6) present in 0.862 g, we need to use the concept of moles and Avogadro's number.

1. Calculate the molar mass of ethane (C2H6):
- 2 carbon atoms (C) with a molar mass of 12.01 g/mol each = 24.02 g/mol
- 6 hydrogen atoms (H) with a molar mass of 1.01 g/mol each = 6.06 g/mol
- Total molar mass of ethane (C2H6) = 24.02 g/mol + 6.06 g/mol = 30.08 g/mol

2. Calculate the number of moles of ethane:
- Moles = Mass / Molar mass
- Moles = 0.862 g / 30.08 g/mol ≈ 0.0286 mol

3. Use Avogadro's number to find the number of molecules of ethane:
- Avogadro's number is approximately 6.022 x 10^23 molecules/mol
- Number of molecules = Moles x Avogadro's number
- Number of molecules = 0.0286 mol x 6.022 x 10^23 molecules/mol ≈ 1.72 x 10^22 molecules

Therefore, there are approximately 1.72 x 10^22 molecules of ethane (C2H6) present in 0.862 g.