mols = grams/molar mass = ?
Then, a mole contains 6.02E23 molecules.
How many molecules are contained in a 7.60-g sample of dimethylmercury?
4 answers
((C H 3) 2 Hg)
2 C = 2 * 12 = 24 g/mol
6 H = 6 g/mol
2 Hg = 2*200.6 = 401 g/mol
sum = 431 grams / mol
so Avagadro's number * 7.6 /431
2 C = 2 * 12 = 24 g/mol
6 H = 6 g/mol
2 Hg = 2*200.6 = 401 g/mol
sum = 431 grams / mol
so Avagadro's number * 7.6 /431
why 2Hg?
Whoops, typo, thanks, 1 Hg
1 answer