How many mol of NaHCO3 are in a 454 g box of baking soda (NaHCO3)?

Question

A. 3.81 x 10^4 mol NaHCO3
B. 1.85 x 10^–1 mol NaHCO3
C. 5.40 x 10^0 mol NaHCO3
D. 6.33 x 10^–20 mol NaHCO3

I tried doing the calculations and a came the closest but it wasn't exact...

Answer 1

Na = 23 g/mol
H = 1
C=12
O3 = 3*16 = 48
sum = 84 grams / mol

454 g * 1 mol/84 grams = 5.40
by the way luckily 10^0 = 1 :)

Answer 2

Thanks Damon! I need help with one more question, I'm about to post it !!

Answer 3

2 years later and he still hasn't posted it... this is a man who sticks to his word -_-

Answer 4

smh

Answer 5

Manz still hasn't posted it

Answer 6

still waiting on question 2

Answer 7

Bro really thinks we have sundials -_-

Answer 8

Its going to be 2023

Answer 9

5 years later and still waiting for that question m8