How many grams of baking soda, NaHCO3, are needed to react with 125 mL of stomach acid having an HCl concentration of 0.05984 M?
The reaction is
NaHCO3(aq) + HCl(aq) → NaCl(aq) + CO2(g) + H2O(l).
Do I need to chenage mL to L first? I'm really stuck with this question. I don't know where to start.
2 answers
I can solve it now. Sorry about the post.
Thanks for letting us know.