How many grams of baking soda, NaHCO3, are needed to react with 125 mL of stomach acid having an HCl concentration of 0.05984 M?

The reaction is

NaHCO3(aq) + HCl(aq) → NaCl(aq) + CO2(g) + H2O(l).

Do I need to chenage mL to L first? I'm really stuck with this question. I don't know where to start.

2 answers

I can solve it now. Sorry about the post.
Thanks for letting us know.