how many mL of a .094 M NaOh are needed to neutralize 21.4 mL of .160 M HCL

Answer 1

HCl + NaOH ==> NaCl + HOH

moles HCl = M x L = ??
Using the coefficients in the balanced equation, convert moles HCl to moles NaOH.
Then M NaOH = moles NaOH/L NaOH and solve for L, then convert to mL.