How many mL of .150 M sodium hydroxide is required to neutralize 25 mL of .125 M of phosphoric acid?

Answer 1

How many mL of a .10 M NaOH solution are needed to neutralize 15 mL of .20 M H3PO4 solution?

Write nbalanced equation:
3NaOH + H3PO4 → Na3PO4 + 3H2O
3mol NaOH recat with 1mol H3PO4

In all these titration questions, do it the simple way: Use the following equation:

Ma*Va/na = Mb*Vb/nb
Where:
Ma = molarity of acid
Va = volume of acid
na = number of moles acid used, from the balanced equation
Mb = molarity of base
Vb = volume of base
nb = number of moles of base used, from the balanced equation:
substitute:
0.20*15/1 = 0.10*Vb/3
Vb = 0.20*15*3 /0.10
Vb = 90ml

The correct answer is : volume of 0.10NaOH required = 90ml.

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Similar problem, different concentrations, volumes, etc.

Just try it yourself! :)