HC2H3O2 + NaOH ==> NaC2H3O2 + H2O
mols acetic acid = M x L = ?
Using the coefficients in the balanced equation, convert mols aceit acid to mols NaOH. You can see the ratio is 1:1.
Then M NaOH= mols NaOH/L NaOH.You know M and mols, solve for L and convert to mL.
2.
KHP + NaOH ==> NaKP + H2O
mols KHP = grams/molar mass
Using ther coefficients in the balanced equation, convert mols KHP to mols NaOH. Again, note the ratio is 1:1 for KHP to NaOH.
Then M = mols/L. You know mols NaOH and L NaOH, solve for M.
1)Calculate the number of mL of a 0.095 M NaOH solution required to neutralize 25.0 mL of 0.15 M acetic acid solution
2) Calculate the molarity of a sodium hydroxide solution if 22.0 mL of the sodium hydroxide is required to neutralize 0.50 g of KHP.
NaOH(aq)+ KHC8H4O4 -> H2O(l) + KNaC8H4O4(aq)
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