How many mL of 0.024M KMn04 (Potassium Permanganate) is required to react with 20mL of 0.112M Fe2+?

Answer 1

Write the equation and balance it.
Calculate moles Fe^2+ = M x L
Using the coefficients in the balanced equation, convert moles Fe^2+ to moles KMnO4.
Then M KMnO4 = mols KMnO4/L KMnO4.Solve for L and convert to mL.